#查詢元素是否在串列list內，有七種方法
#(1).if txt in a
#(2).res = a.index(s)
#(3).matches = [x for x in lst if fulfills_some_condition(x)]
#(4).matches = (x for x in lst if x > 6)
#(5).next(x for x in lst if ...)
#(6).for index, sublist in enumerate(lists):
#if sublist[0] == key:
#(7).[i for i,x in enumerate([1,2,3,2]) if x==2]

#方法1：if txt in a
a=['tom','mike','peter','yellow']
def find_list(txt,a):
    if txt in a:
        return txt + '存在list內'
    else:
        return txt + '不存在list內'
    
txt = input('請輸入查詢姓名？')
res = find_list(txt,a)
print(res)