如何建立1按鈕，顯示複選餐點項目，結果顯示在editText上


注意：整個事件程式碼都必須放在
onCreate() 
{  
}
下面
..........................

範例：


import android.view.*;
import android.widget.*;
import android.app.AlertDialog;
import android.content.DialogInterface;

import android.app.Dialog;


	
	String[] items = {"項目一", "項目二", "項目三"};
	boolean[] itemsChecked = new boolean[items.length];
	
    protected Dialog onCreateDialog(int id) {
        switch (id) {
      	case 0: // 傳回AlertDialog對話方塊
      		return new AlertDialog.Builder(this)
      		.setTitle("輸出所要顯示的訊息文字?")
      		.setPositiveButton("確定",
      		 new DialogInterface.OnClickListener() { 
      	        public void onClick(DialogInterface  
      	                     dialoginterface, int i) {    	                  
      	           String msg = "";
      	           for (int index = 0; index < items.length; index++) {
      	           	  if (itemsChecked[index])
      	                  msg += items[index] + "\n";        	   
      	           }
      	           TextView output = (TextView) findViewById(R.id.editText1);
      	           output.setText(msg);
      	        } 
      	     }) 
      	    .setNegativeButton("取消", null) 
      	    .setMultiChoiceItems(items,itemsChecked, 
      	     new DialogInterface.OnMultiChoiceClickListener() {
  				public void onClick(DialogInterface dialog, int which, boolean isChecked) {
  				   //Toast.makeText(this,items[which] + (isChecked ? " 勾選": "沒有勾選"),Toast.LENGTH_SHORT).show();   	 
  				}
  			 })
      	    .create();
        }
        return null;
      }
      // button1事件處理程序
      public void button1_Click(View view) {    	
        showDialog(0); // 顯示對話方塊        
      }